How much does a data scientist make in Norwich?
$101,900a year
Median yearly pay for data scientists in the Norwich-New London-Willimantic, CT metro area. That is $49.01 an hour or $8,495 a month.
- Hourly
- $49.01
- Vs. national median
- -15%
- Rank among cities
- 114 of 282
- Jobs in the area
- 60
Pay range
Lowest 10%: $76,370Median: $101,900Highest 10%: $161,400
| Percentile | Yearly | Hourly | |
|---|---|---|---|
| 10th | $76,370 | $36.72 | |
| 25th | $87,090 | $41.87 | |
| Median | $101,900 | $49.01 | |
| 75th | $133,100 | $63.98 | |
| 90th | $161,400 | $77.57 |
Other cities in Connecticut
Median yearly pay for data scientists.
| Bridgeport, CT | $141,800 |
| Hartford, CT | $126,300 |
| New Haven, CT | $121,900 |
| Waterbury, CT | $59,160 |
Related jobs in Norwich
Same field, median yearly pay.
| Computer Network Architect | $135,000 |
| Software Developer | $123,800 |
| Computer Programmer | $116,400 |
| Computer Occupation | $112,100 |
| Network and Computer Systems Administrator | $105,900 |
| Information Security Analyst | $101,900 |
| Computer Systems Analyst | $101,400 |
| Software Quality Assurance Analyst and Tester | $98,720 |
| Computer User Support Specialist | $62,710 |
Frequently asked questions
How much does a data scientist make an hour in Norwich?
The median hourly pay in the Norwich-New London-Willimantic, CT metro area is $49.01 ($101,900 a year).
Do data scientists make more in Norwich than the national average?
No: $101,900 against $120,200 nationally, 15% less.
How does Norwich compare with the rest of Connecticut?
The median in Connecticut is $126,300, so Norwich pays 19% less.
Where does Norwich rank for data scientist pay?
114 of 282 metro areas with data.
How much does a data scientist make starting out in Norwich?
The lowest-paid 10% make $76,370 or less a year; the top 10% make $161,400 or more.
Source: U.S. Bureau of Labor Statistics, Occupational Employment and Wage Statistics (OEWS): pay in May 2025, published by BLS in 2026. Hourly pay is the yearly figure divided by 2,080 hours.