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How much does a healthcare diagnosing or treating practitioner make in Wyoming?

$101,300a year

Median yearly pay for healthcare diagnosing or treating practitioners in Wyoming. That is $48.69 an hour or $8,440 a month.

Hourly
$48.69
Vs. national median
-12%
Rank among states
21 of 43
Jobs in the state
40
Pay range
Lowest 10%: $46,880Median: $101,300Highest 10%: $154,800
PercentileYearlyHourly
10th$46,880$22.54
25th$80,770$38.83
Median$101,300$48.69
75th$121,400$58.36
90th$154,800$74.41

Cities in Wyoming

Metro areas, median yearly pay.

No city data for this job.
Salaries for every job in Wyoming

Nearby in the ranking

States with similar pay for healthcare diagnosing or treating practitioners.

18. Pennsylvania$103,200
19. Ohio$101,700
20. Colorado$101,600
21. Wyoming$101,300
22. North Dakota$101,200
23. New Jersey$100,900
24. Minnesota$99,400
Healthcare Diagnosing or Treating Practitioner salary in all states

Frequently asked questions

How much does a healthcare diagnosing or treating practitioner make an hour in Wyoming?

The median hourly pay in Wyoming is $48.69 ($101,300 a year).

Do healthcare diagnosing or treating practitioners make more in Wyoming than the national average?

No: $101,300 against $115,200 nationally, 12% less.

Where does Wyoming rank for healthcare diagnosing or treating practitioner pay?

Wyoming ranks 21 of 43 states.

Source: U.S. Bureau of Labor Statistics, Occupational Employment and Wage Statistics (OEWS): pay in May 2025, published by BLS in 2026. Hourly pay is the yearly figure divided by 2,080 hours.