How much does a skincare specialist make in Lexington?
$38,580a year
Median yearly pay for skincare specialists in the Lexington-Fayette, KY metro area. That is $18.55 an hour or $3,215 a month.
- Hourly
- $18.55
- Vs. national median
- -15%
- Rank among cities
- 156 of 222
- Jobs in the area
- 180
Pay range
Lowest 10%: $27,520Median: $38,580Highest 10%: $58,250
| Percentile | Yearly | Hourly | |
|---|---|---|---|
| 10th | $27,520 | $13.23 | |
| 25th | $27,600 | $13.27 | |
| Median | $38,580 | $18.55 | |
| 75th | $45,840 | $22.04 | |
| 90th | $58,250 | $28.00 |
Other cities in Kentucky
Median yearly pay for skincare specialists.
| Cincinnati, OH | $43,570 |
| Louisville, KY | $38,750 |
| Clarksville, TN | $36,300 |
Related jobs in Lexington
Same field, median yearly pay.
| Exercise Trainer and Group Fitness Instructor | $48,600 |
| First-Line Supervisors of Personal Service Worker | $44,550 |
| First-Line Supervisors of Entertainment and Recreation Worker | $41,770 |
| Residential Advisor | $41,600 |
| Concierge | $35,810 |
| Tour and Travel Guide | $35,160 |
| Childcare Worker | $35,100 |
| Animal Caretaker | $34,590 |
| Animal Trainer | $34,310 |
| Recreation Worker | $32,720 |
Frequently asked questions
How much does a skincare specialist make an hour in Lexington?
The median hourly pay in the Lexington-Fayette, KY metro area is $18.55 ($38,580 a year).
Do skincare specialists make more in Lexington than the national average?
No: $38,580 against $45,330 nationally, 15% less.
How does Lexington compare with the rest of Kentucky?
The median in Kentucky is $38,580, so Lexington pays 0% more.
Where does Lexington rank for skincare specialist pay?
156 of 222 metro areas with data.
How much does a skincare specialist make starting out in Lexington?
The lowest-paid 10% make $27,520 or less a year; the top 10% make $58,250 or more.
Source: U.S. Bureau of Labor Statistics, Occupational Employment and Wage Statistics (OEWS): pay in May 2025, published by BLS in 2026. Hourly pay is the yearly figure divided by 2,080 hours.